Question

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

A. 19.2 units

B. 22.3 units

C. 27.4 units

D. 36.0 units

Answer 1

its is 27.4 units just square it out 

Answer 2

The correct answer is C

Step-by-step explanation

We use the distance formula to determine the length of each side and add them.

The vertices of the triangle has coordinates
`B(-1,7)`,
`C(6,3)` and
`B(-4,-1)`.

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

`|AB|=√((-1--4)^2+(7--1)^2)`

`|AB|=√((-1+4)^2+(7+1)^2)`

`|AB|=√((3)^2+(8)^2)`

`|AB|=√(9+64)`

`|AB|=√(73)`

`|AB|=8.54` units

`|BC|=√((-1-6)^2+(7-3)^2)`

`|BC|=√((-7)^2+(4)^2)`

`|BC|=√(49+16)`

`|BC|=√(65)`

`|BC|=8.06` units

`|AC|=√((-4-6)^2+(-1-3)^2)`

`|AC|=√((-10)^2+(-4)^2)`

`|AC|=√(100+16)`

`|AC|=√(116)`

`|AC|=10.77` units

`Perimeter=|AC|+|BC|+|AB|`

`Perimeter=10.77+8.06+8.54`

`Perimeter=27.4` units