To make this as easy as possible, we will find the vertex from the equation above. The vertex is sitting at (h, k) of (2, -3). The directrix is the same number of units from the vertex that the focus is. The formula for the focus for an upwards-opening parabola is
![(h,k+ (1)/(4a) )](https://img.qammunity.org/2019/formulas/mathematics/high-school/hgbe79ykk6lnma8kl0dba8l3bakg55hars.png)
. The "a" in that formula is the 1/4 sitting in front of (y+3). Filling in accordingly, we have
![(2, -3+ (1)/(4( (1)/(4)) ))](https://img.qammunity.org/2019/formulas/mathematics/college/5rwdnop6sw6qynujix4bxyak5hb9iu5kps.png)
. Simplifying we get
![(2, -3+1)=(2, -2)](https://img.qammunity.org/2019/formulas/mathematics/college/48j3o1ch41b6rf9re4k9l6y0w9tbjd6e3a.png)
. The focus is on the axis of symmetry along with the vertex, and is 1 unit above the vertex. That means that the directrix is 1 unit BELOW the vertex and is a horizontal line. Therefore, the directrix has an equation of y = -4