Question

The value of gravitational acceleration of a body on Earth is 9.8 meters/second2. The gravitational potential energy for a 1.00 kilogram object is found to be 12.5 joules. How high is this object above the ground level, where PE = 0?

A. 1.3 Meters
B. 3.5 Meters
C. 2.0 Meters
D. 5.6 Meters
E. 7.9 Meters

Answer 1

E = mgh

h = E / mg = 12.5 / (1 * 9.8) m = 1.275510204 m ~ 1.3 m (answer A)

Answer 2

Given data

Gravitational acceleration (g) = 9.8 m/s² ,

Gravitational potential energy (P.E) = 12.5 Joules,

Mass of the body (m) = 1 kg,

Determine,

Height of the object above the ground level (h) = ?

We know that,

the gravitational potential energy is defined as "the energy of an object possesses because of its position in a gravitational field".

Mathematically ,

P.E. = m.g.h Joules

=> h = P.E/m.g meters

= 12.5 J/ (1 kg×9.8 m/s²)

= 1.275 m ≅ 1.3 m

Therefore, the height (h) of the object above the ground is 1.3 meters.

So, Answer A is correct..