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The latent heat of vaporization for ethyl alcohol is 854 J/g. The amount of energy, rounded to the nearest whole number, needed to change 5.20 grams of ethyl alcohol from a liquid to a gas is _____ J.

User Voidstate
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2 Answers

2 votes

Answer:

4,441

Step-by-step explanation:

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User Mhartington
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L = latent heat of vaporization for ethyl alcohol = 854 J/gram

m = mass of the ethyl alcohol to change from liquid to gas = 5.20 grams

Q = heat of vaporization required to change from liquid to gas = ?

heat of vaporization required to change from liquid to gas is given as

Q = m L

inserting the values

Q = (5.20 grams) (854 J/gram)

Q = (5.20 x 854) (J/gram) (gram)

Q = 4440.8 Joules

so heat of vaporization comes out to be 4440.8 Joules.

User Kanani
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