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Please help me.

What is the equation of the line?

Please help me. What is the equation of the line?-example-1
User Konny
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1 Answer

10 votes

Answer:


y = (-7)/(3)x -12

Explanation:

Point-slope form is
y-y_1= m (x-x_1). The
m,
x_1, and
y_1 have to be substituted for with real values in order to make an equation of a line. From there, you can isolate
y to turn it into slope-intercept form.

1) First, let's find the slope of the line, which is represented by the variable
m. Use the slope formula,
(y_2-y_1)/(x_2-x_1), to find the slope.
x_1 and
y_1 are the x and y values of one point,
x_2 and
y_2 are the x and y values of another point. For this problem, let's use the given points (-3, -5) and (-6, 2):


((2)-(-5))/((-6)-(-3)) \\= (2+5)/(-6+3) \\= (7)/(-3)

Thus, the slope is
(7)/(-3).

2) Now that we have the slope, let's substitute it into the point-slope formula. The
x_1 and
y_1 represent the x and y values of a point that the line intersects so you could either use (-3, -5) or (-6,2), but for this answer, I used (-6,2). (The answer will always be the same no matter which point you choose.) Substitute these values then isolate y to put it in slope-intercept form:


y-(2) = (-7)/(3) (x-(-6))\\y -2 = (-7)/(3) (x+6)\\y-2 = (-7)/(3)x-(42)/(3) \\y -2 = (-7)/(3)x-14\\y = (-7)/(3)x-12

So,
y = (-7)/(3)x -12 is the answer.

User Mark Woon
by
8.2k points

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