Answer:
f'(x) = 2.x.tan(x) + x²/cos²(x)
Explanation:
f(x) = x².tan(x)
=> f'(x) = (x²)' . tan(x) + x². (tan(x))'
= 2x.tan(x) + x² . 1/cos²(x)
=> f'(x) = 2.x.tan(x) + x²/cos²(x)
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