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The product of two consecutive positive integers is 1111 more than their sum. find the integers.

1 Answer

5 votes
the correct question is
The product of two consecutive positive integers is 11 more than their sum. find the integers.

Let
x-------> the first positive integer
x+1-----> the second consecutive positive integer

we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
x²-x-12=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solution is
x=4

therefore

the numbers are
x=4
x+1=5

the answer is
the numbers are 4 and 5

The product of two consecutive positive integers is 1111 more than their sum. find-example-1
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