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What is the calculated molar concentration of the Cl⁻ ions in 0.87 M MgCl2(aq)?

User BluePrint
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MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.87 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.7 M
The answer to this question is [Cl⁻] = 1.7 M
User Gnadelwartz
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