Question

Calculate the molar concentration of the Cl⁻ ions in 0.54 M AlCl3(aq), assuming that the dissolved substance dissociates completely in solution.

Answer 1

AlCl3(aq) is an ionic compound which will have the releasing of 3 Cl⁻ ions ions in water for every molecule of AlCl3 that dissolves.
AlCl3(s) --> Al+(aq) + 3 Cl⁻(aq)
[Cl⁻] = 0.54 mol AlCl3/1L × 3 mol Cl⁻ / 1 mol AlCl3 = 1.6 M
The answer to this question is [Cl⁻] = 1.6 M