Question

If 0.1718 l of a 0.3556-m c3h7oh solution is diluted to a concentration of 0.1222 m, what is the volume of the resulting solution

Answer 1

Answer: 0.5 Liters

Explanation :

The dilution law is:

`M_1V_1=M_2V_2`

where,

`M_1` = concentration of stock solution = 0.3556 M

`M_2` = concentration of resulting solution = 0.1222 M

`V_1` = volume of stock solution= 0.1718 L

`V_2` = volume of resulting solution = ?

Now put all the given values in the above law, we get the volume of the resulting solution.

`(0.3556* 0.1718=(0.1222* V_2)`

`V_2=0.5L`

Thus the volume of the resulting solution is 0.5 Liters.

Answer 2

Answer : The volume is found to be 0.4999 L.

Explanation : In the given case, the two concentrations of the solution are given and the volume concentration given for one and other needs to be identified.

So, according to the formula :-
`m _(1)V_(1)=m_(2) V_(2)`

Here suppose the
`V _(1)` is 0.1718 L moles and
`m _(1)` as 0.3556 moles, then we need to determine the
`V _(2)` as
`m _(2)` is mentioned as 0.1222 moles.

Therefore from the formula we get,
`m _(1)V_(1)=m_(2) V_(2)`

So,
`V_(2)` = (0.1718 X 0.3556) / 0.1222 = 0.4999 L