Question

How many moles of glucose, c 6 h 12 o 6 , can be "burned" biologically when 10.0 mol of oxygen is available? c 6 h 12 o 6 ( s ) + 6o 2 ( g ) → 6co 2 ( g ) + 6h 2 o( l )?

Answer 1

Answer is 1.67 moles of glucose.

Explanation :

With the presence of oxygen glucose produces CO₂ and H₂O.
The balanced equation is
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)

The stoichiometric ratio between C₆H₁₂O₆(s) and 6O₂(g) is 1 : 6.
Hence,
moles of C₆H₁₂O₆(s) reacted = moles of reacted O₂(g) / 6
= 10.0 mol / 6
= 1.67 mol