Question

A car slows down at -5.00 m/s^2 until it comes to a stop after traveling 15.0 m. What was the initial speed of the car?

Answer 1

The initial speed of the car was 12.2 m/s.

Step-by-step explanation:

To find the initial speed of the car, we can use the equation v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity, a is the acceleration (-5.00 m/s^2), and s is the distance traveled (15.0 m). Rearranging the equation, we get u = sqrt(v^2 - 2as). Plugging in the values, we get u = sqrt(0 - 2*(-5.00)*15.0) = sqrt(150.0) = 12.2 m/s.

Answer 2

8.66mls = v1

vf2 = vi2 + a(d)
(0mls) squared = visquared + - 5mls squared (15m)
0mls squared = vi2 - 75m squared / s squared

`√(x)` 75 m squared/s squared = vi

Hope this helps!