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What are the solutions of the equation x^2= 7x+4?

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x^2 = 7x + 4

x^2 - 7x - 4 = 0

This polynomial is not factorable, so we can use the quadratic formula with a = 1, b = -7, and c = -4


x = (-b \pm √(b^2 - 4ac))/(2a)


x = (-b \pm √(b^2 - 4ac))/(2a)


x = (-(-7) \pm √((-7)^2 - 4(1)(-4)))/(2(1))


x = (7 \pm √(49 + 16))/(2)


x = (7 \pm √(65))/(2)


x = (7)/(2) + (√(65))/(2) or
x = (7)/(2) - (√(65))/(2)
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