we are given
equilateral triangle
we can see that triangle ACD is a right angled triangle
so, we can use Pythagoras theorem for this triangle
hypotenuse=AC
Adjacent=CD
opposite=AD=a
and
![AC=6√(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wdwfiikpgdh40oqqsvh8o8kcnudi1dpnfw.png)
![CD=3√(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ojmqrcsfbjnoe3n9rgpr4ecp4177ue9lqp.png)
![AD=a](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jdmvld819lqtp3gmqjsxes9mu8p6wmz2ki.png)
now, we can use Pythagoras theorem
and we get
![AC^2=CD^2+AD^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/gatcxyydkspfmanbdcrvg2avdrtd55m63v.png)
now, we can plug values
![(6√(3) )^2=(3√(3) )^2+a^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/q7jstfrh9hylwt70ldnxq2xw7cg407n72d.png)
now, we can solve for a
![108=27+a^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8ywi49njy6klwogbu1mwe2463kibx2k1ew.png)
![27+a^2-27=108-27](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cua373r693or7dbyd5ocflor202houp4fz.png)
![a^2=81](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2vvo984m6yyukjhorsvjs03ijwx9y1fu38.png)
![a=9](https://img.qammunity.org/2019/formulas/mathematics/high-school/iqbdeymi9mijo7e1bf7h58mrig7e7ervm1.png)
so, option-A..........Answer