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Please Help... Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 14 = 0

User Vroldan
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1 Answer

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the question does not present the options, but this does not interfere with the resolution

Part 1)

− 9a + 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² − 9a) =-14
Complete the square. Remember to balance the equation by adding the same constants to each side
(a² − 9a+20.25) =-14+20.25
Rewrite as perfect squares(a-4.5)² =6.25
(+/-)[a-4.5]=√6.25-------- (+/-)[a-4.5]=2.5(+)[a-4.5]=2.5----> a=7
(-)[a-4.5]=2.5-----> a=2
the answer part 1) a=7 and a=2

Part 2) a² + 9a + 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 9a) =-14
Complete the square. Remember to balance the equation by adding the same constants to each side
(a² + 9a+20.25) =-14+20.25
Rewrite as perfect squares(a+4.5)² =6.25
(+/-)[a+4.5]=√6.25-------- (+/-)[a+4.5]=2.5(+)[a+4.5]=2.5----> a=-2
(-)[a+4.5]=2.5-----> a=-7
the answer part 2) a=-7 and a=-2
Part 3) a² + 3a - 10 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 3a) =10
Complete the square. Remember to balance the equation by adding the same constants to each side
(a² + 3a+2.25) =10+2.25
Rewrite as perfect squares(a+1.5)² =12.25
(+/-)[a+1.5]=√12.25-------- (+/-)[a+1.5]=3.5(+)[a+1.5]=3.5----> a=2
(-)[a+1.5]=3.5-----> a=-5
the answer part 3) a=2 and a=-5
Part 4) a² + 5a - 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 5a) =14
Complete the square. Remember to balance the equation by adding the same constants to each side
(a² + 5a+6.25) =14+6.25
Rewrite as perfect squares(a+2.5)² =20.25
(+/-)[a+2.5]=√20.25-------- (+/-)[a+2.5]=4.5(+)[a+2.5]=4.5----> a=2
(-)[a+2.5]=4.5-----> a=-7
the answer part 4) a=2 and a=-7
Part 5) a² - 5a - 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² - 5a) =14
Complete the square. Remember to balance the equation by adding the same constants to each side
(a² - 5a+6.25) =14+6.25
Rewrite as perfect squares(a-2.5)² =20.25
(+/-)[a-2.5]=√20.25-------- (+/-)[a-2.5]=4.5(+)[a-2.5]=4.5----> a=7
(-)[a-2.5]=4.5-----> a=-2
the answer part 5) a=7 and a=-2
User IndustryDesigns
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