Question

Y=8(x^2+4)+17+-32 in vertex form

Answer 1

`y = 8( {x}^(2) + 4) + 17 + ( - 32)`

`y = 8( {x}^(2) + 4) + 17 - 32`

`y = 8 {x}^(2) + 32 + 17 - 32`

`y = 8 {x}^(2) + 17`
compare to the formula:

`y = a( {x}^(2) - h) + k`

`y = 8( {x}^(2) - 0) + 17`
a = 8
h = 0
k = 17