Question

Consider the function f(x) = 1/3(6)x. What is the value of the growth factor of the function?

A.1/3
B.2
C.6
D.18

Answer 1

the answer is c to this question

Answer 2

growth factor is 6

Explanation:

`f(x) =(1)/(3) (6)^x`

For any equation f(x)=ab^x

'a' is the initial value

b is the growth or decay factor .

When the value of b is greater than 1 then its growth factor

when the value of b is between 0 and 1 then it is decay factor

x is the number of years

In our given function

`f(x) =(1)/(3) (6)^x`

the value of b is 6

so growth factor is 6