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One positive integer is 3 units more than another. When the reciprocal of the larger is subtracted from twice the reciprocal of the smaller, the result is 2/9. Find the two positive integers.

1 Answer

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x=y+3
(2/y)-(1/x)=2/9
Use systems of equations, plug x-3 for y
(2/x-3)-(1/x)=2/9
y= 6, -9/2
Therefore, x = 9, -3/2
But it's positive, so the integers are 6 and 9
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