Question

6th question help please

Answer 1

you would have to find the area of each triangle and the square then add it together so use the area equation for a triangle which is
B=Base H=Height
A= B x H/2

so with the numbers given in the question you would plug them in and get

A= 2 x 3/2

2 x 3= 6

6/2= 3

area of triangle is 3 in^2

so since there are 4 triangles and we just found the area of one you can multiply the area by 4 since all the triangles are the same and the area of all the triangles together is 12 so now all you have to do is add the area of the square

so to find the area of the square you use this equation

a = b x h

so plug your number s in and you get


a = 2 x 2
so the area of the square is 4

now add them all up and the surface are of the pyramid is 16

Answer 2

Hey there! :)

You have to find the area of ALL of them and add it together.

Formulas:

Area of a triangle ⇒ (b · h) ÷ 2
Area of a square ⇒ l · w

Square -

l = 2
w = 2

2 × 2 = 4

Triangle -

b = 2
h = 3

(3 × 2) ÷ 2
6 ÷ 2 = 3

There are 4 triangles

3 × 4 = 12

12 + 4 = 16

The surface area = 16 in²

Hope this helps :)