Question

I NEED HELP

Can anyone help?

so with the formula

`f(x) = - {x}^(2) + hx - 5`
I need to state the coordinates of A..

Answer 1

The coordinates of A are a point on the y, axis, making this the y intercept.

For such points, the x coordinate will always be 0, so simply plug in 0 for x in your equation

f(0) = -0^2 + h*0 - 5 = -5.

So A's coordinate will be (0,-5)

Answer 2

Point A is y-intercept of the graph of the function f(x) = -x² + hx - 5.

For y-intercept x=0,
so f(0) = -0² + h*0 - 5 = - 5.
f(0) = - 5.

So, coordinates of the point A are x=0, f(0)= y = - 5.
A(0, - 5)