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4 votes
Which of the following is equal too
√(-8)

A) 2
√(2)

B) -2
√(2)

C) 2i
√(2)

D) 2
√(2i)

User Anregen
by
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1 Answer

5 votes
You can't have a negative number under a radical that has an even index. We have an even index since we are dealing with the square root. Because of that we have to get the imaginary i involved.
i^2=-1. Keeping that in mind, let's rewrite our problem:
√((-1)(8)). If -1 equals i-squared, we can sub that in. Also, since 8 = 4*2 and 4 is a perfect square, let's break that down at the same time:
√(i^2(4)(2)). i-squared is a perfect square which can be pulled out as a single i, and 4 is a perfect square which can be pulled out as a 2. We will leave a 2 under the radical. Here's your simplification:
2i √(2), choice C from above.
User IngoAlbers
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