Final answer:
The ions that result from the dissociation of Na2S are 2Na+ and S2-.
Step-by-step explanation:
The dissociation of Na2S can be represented by the following chemical equation:
Na2S(aq) → 2Na+(aq) + S2-(aq)
In this equation, Na2S dissociates into two sodium ions (Na+) and one sulfide ion (S2-). Each sodium ion carries a +1 charge, while the sulfide ion carries a -2 charge.
Therefore, the ions that result from the dissociation of Na2S are 2Na+ and S2-.