187k views
5 votes
Determine how many moles of copper(ii) chloride are in 15.00 ml of a 0.500m solution.

2 Answers

6 votes
Answer : To calculate the number of moles of copper (II) chloride in 15.0 ml of 0.500 M solution, you have to simply use the given calculation:

15 (ml) X 0.500 (moles) / 1000 (mL) = 0.00750 moles of CuCl₂ .


User AyB
by
5.2k points
7 votes

Answer: The number of moles of Copper (II) chloride is 0.0075mol.

Step-by-step explanation:

From the definition of molarity, it is the number of moles of solute in 1L or 1dm³ of a solution. It has the unit of mol/dm³ or mol/L or simply M

It can be expressed as

Molarity = moles of solute / volume of solution

Given that ;

molarity =0.50M

Volume of solution =15mL= 15× 10^-3

moles of solute (Copper (II) Chloride) =?

0.50 = moles of solute /15×10^-3

Moles = 0.50 × 15×10^-3

Moles = 7.5 ×10^-3mole

Therefore moles of Copper (II) chloride = 0.0075mol.

User Merk
by
6.1k points