Question

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to

gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is –9.8 m/s2.

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

Answer 1

The answer is C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

option C

Explanation:

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity. The acceleration due to gravity is –9.8 m/s2

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

g= -9.8, v0 = 20 and h0 = 60

So the equation becomes

`h(t)= -9.8t^2 +20t +60`

When the object hit the ground the height =0 so we replace h(t)=0

Apply quadratic formula

`t= (-b+-√(b^2-4ac))/(2a)`

a= -9.8 , b=20 and c= 60

`t= (-20+-√((20)^2-4(-9.8)(60)))/(2(-9.8))`