Question

‼️‼️Help anyone ‼️‼️‼️

Answer 1

Method 1
You can use The equilateral triangle (look at the picture)

`(a\sqrt3)/(2)=1\ \ \ \cdot2\\\\a\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3a=2\sqrt3\ \ \ |:3\\\\a=(2\sqrt3)/(3)\\\\\boxed=(2\sqrt3)/(3)`


Method 2
You can use the trigonometric function

`\sin60^o=(1)/(|AC|)\\\\\sin60^o=(\sqrt3)/(2)\\\\(1)/(|AC|)=(\sqrt3)/(2)\ \ \ |\cross\ multiply\\\\|AC|\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3|AC|=2\sqrt3\ \ \ \ |:3\\\\\boxed=(2\sqrt3)/(3)`