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What is the equation of the following graph in vertex form

What is the equation of the following graph in vertex form-example-1
User Aitwar
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1 Answer

3 votes

Answer:

The first option,
y=(x-2)^2+1

Explanation:

Because the graph is showing a quadratic function we need to start by the equation of a quadratic function in its vertex form, which is:


y=a(x-h)^2+k, where:

a= is a transformation coefficient

(h,k)=vertex coordinates

Because the vertex is (2,1) then h=2 and k=1, using the vertex form we obtain:


y=a(x-2)^2+1

Now, because we have an extra point (0,5), we can find 'a' as follows:


5=a(0-2)^2+1, which can be simplified as:


5=4a+1


a=(5-1)/4


a=1

Then the vertex form of the graph is:


y=(x-2)^2+1, which is the first option.

User Azar
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