Question

Please answer this with solution thanks​

Answer 1

Function 1 is neither odd nor even

Function 2 is odd

Explanation:

Here, you must first understand the expression of odd and even functions:

Even: f(x) = f(-x)

Odd: f(-x) = -f(x)

Question 1:

`{ \tt{f(x) = x + 3}} \\ { \rm{when \: x = - x}} \\ { \tt{f( - x) = - x + 3}} \\ { \tt{f( - x) \: is \: neither \: even \: nor \: odd }}`

Question 2:

`{ \tt{f(x) = - { \green{{3x}^(3) + 6x }}}} \\ { \rm{when \: x = - x}} \\ { \tt{f( - x) = - 3 {( - x)}^(3) + 6( - x) }} \\ { \tt{f( - x) = 3 {x}^(3) - 6x}} \\ { \tt{f( - x) = - \{ { \green{- 3 {x}^(3) + 6x }}}} \} \\ { \tt{f( - x) = - f(x)}}`