Question

Find the sum of the geometric sequence. 4 divided by 3, 8 divided by 3, 16 divided by 3, 32 divided by 3, 64 divided by 3

Answer 1

So this problem is just adding the dividends so it would be 4/3+8/3+16/3+32/3+64/3 so it would be 124/3 or 41.33333

Answer 2

41.333

Explanation:

Given is a geometric sequence

`(4)/(3) ,(8)/(3) ,(16)/(3) ,(32)/(3) ,(64)/(3)`

No of terms n =5

a = I term =
`(4)/(3)`

Use the formula for sum of geometric sequence when r >1

`S_n =(a(r^n-1)/(r-1) \\=(4)/(3)[( (2^5-1)/( 2 -1)] \\=4((31)/(3) )\\=41.3333`