Lets start by factoring the 216 into its smaller parts.
![\sqrt[3]{2 * 2 * 2 * 3 * 3 * 3}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qoiq83gzf24qdnerq79xg4c6lam88zqpsj.png)
From here, we can separate the three 2s and the three 3s into two separate radicals.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ey3jrrojs2suqqimtz6xv1xelwg2hat3sw.png)
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3} = 2 * 3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pv7ph8e7qxr756wj2x6pmwmkgbpwmpkasp.png)
Finally, we just need to multiply out what remains to find the solution.

So, the final answer is 6.