I recommend solving the second equation above for y. That will be y=4x-4. Now sub that value of y into the first equation for y and get 2x+2(4x-4)=1. Expand to get 2x + 8x - 8 = 1. Combine like terms and we get 10x = 9 and
![x= (9)/(10)](https://img.qammunity.org/2019/formulas/mathematics/high-school/m8lmqcmglkw2emox4mumw965geebxvgn4b.png)
. Now we need to plug that x value into any equation we have to solve for y (your "b").
![2( (9)/(10))+2y=1](https://img.qammunity.org/2019/formulas/mathematics/high-school/g0poshb8d2hu262lrntsup6vetpv03ugw1.png)
and
![(9)/(5)+2y=1](https://img.qammunity.org/2019/formulas/mathematics/high-school/ftf9mb72bfqk7al3a7006i9d83hsjznizb.png)
. Then
![2y= (5)/(5)- (9)/(5) = (-4)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/b949n6odj9htsg4of846rvltrcwbdsdk59.png)
. Multiplying both sides by 1/2 gives us that y = -2/5. That's your "b" value you're looking for.