Question

Please help me answer this with solution​

Answer 1

Question 1:

`{ \tt{f(x) = {x}^(2) - 10x + 25}}`

when f(x) is f(10), we substitute for x as 10; x = 10

`{ \tt{f(10) = {10}^(2) - 10(10) + 25 }} \\ { \tt{f(10) = 100 - 100 + 25}} \\ { \boxed{ \tt{ \: f(10) = 25 \: }}}`

Question 2:

`{ \tt{f(x) = \frac{2 {x}^(3) - 7 }{10} }} \\`

when f(x) is f(-1), we substitute for x as -1; x = -1

`{ \tt{f( - 1) = \frac{2 {( - 1)}^(3) - 7 }{10} }} \\ \\ { \tt{f( - 1) = ( - 2 - 7)/(10) }} \\ \\ { \boxed{ \tt{ \: f( - 1) = - (9)/(10) \: }}}`