Answer:
The area under the normal curve between 400 and 482 is
![0.4495](https://img.qammunity.org/2019/formulas/mathematics/high-school/n3xmpde8m9j6sogvrjugycsdka2rmhp4ne.png)
Explanation:
Let's start defining the random variable.
: ''Efficiency ratings''
We know that the distribution of
approximates a normal distribution ⇒
~
(μ,σ)
Where the normal distribution is defined by the parameters μ (mean) and σ (standard deviation) ⇒
We know that the mean is 400 and the standard deviation is 50 ⇒
~
![(400,50)](https://img.qammunity.org/2019/formulas/mathematics/high-school/e3axtjvcnbe6nkg8au00ah249fwsk8v5b0.png)
The area under the normal curve between 400 and 482 represents the probability of the variable (
in this case) to assume values between 400 and 482.
We need to calculate :
![P(400<X<482)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ltmz9awo5c1ypfkx8m3r7i8stpl76e3k31.png)
We can standardized this variable by subtracting the mean and then dividing by the standard deviation.
The new variable (X-μ)/σ is called Z
The distribution of Z is
~
![N(0,1)](https://img.qammunity.org/2019/formulas/mathematics/high-school/28fqxch5zwyjsh4dr8q67ywtf5rfbbjt00.png)
The probabilities of Z are in any table on internet.
To calculate
we can use Φ(a) where Φ is the cumulative function of Z.
Solving the exercise :
⇒
⇒
![P(0<Z<1.64)](https://img.qammunity.org/2019/formulas/mathematics/high-school/5b99yixpzzp8aj2zl08ijds6kn2icbukj0.png)
We find that
![P(400<X<482)=P(0<Z<1.64)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ilhrx2s1yy4a62hokqaa8ccqnelatv5tsq.png)
Looking for the values of the cumulative function of Z in any table we can write :
Φ(1.64) - Φ(0) = 0.9495 - 0.500 = 0.4495
We find that the probability is 0.4495 and therefore the area under the normal curve (of X) between 400 and 482 is 0.4495