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Calculate the solubility of FeF2 in water by using 2.36 x 10 -6 as the solubility product.

User SiZE
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Answer:

The person above is correct

Step-by-step explanation:

User Andy Nichols
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FeF₂(s) ⇄ Fe²⁺ + 2 F⁻

let x = [FeF₂]. then [Fe²⁺] = x and [F⁻] = 2x (by the reaction)

Ksp = [
Fe²⁺][F⁻]²
2.36 x 10⁻⁶ = x(2x)²
x = 8.387 × 10⁻³ M =
[FeF₂]

the solubility of
FeF₂ in water is 8.39 × 10⁻³ M
User Jason Stangroome
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