Question

What is the equation of a line passing through (-6,5) and having a slope of 1/3 (1 over 3) ?

a) y= 1//3 x - 23/3
b) y=1/3 x - 3
c) y= 1/3 x + 7 
d) y= 3x+7

Answer 1

`\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\qquad \qquad \qquad slope = m \implies \cfrac{1}{3} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=\cfrac{1}{3}[x-(-6)]\implies y-5=\cfrac{1}{3}(x+6) \\\\\\ y-5=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+7`

Answer 2

The answer is y=(1/3)x+7, use y=mx+b and solve for b where m is slope