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Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
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Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

User Ferhado
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1 Answer

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The value of b is -21. To find the slope of the line use the slope formula:
(y^2 - y^1)/( x^(2) - x^1). The slope is -4. Then you plug in one coordinate to find the value of b.
User Aromore
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