Question

Write the equation in standard form then factor the left side of the equation 2x'2+7x=15

Answer 1

`given \: equation - - - > \\ 2 {x}^(2) + 7 x = 15 \\ \\ standard \: form - - - > \\ 2 {x}^(2) + 7x - 15 = 0 \\ \\ factorising \: left \: side - - - > \\ \\ = > 2 {x}^(2) + 7x - 15 \\ \\ = > 2 {x}^(2) + 10x - 3x - 15 \\ \\ = > 2x(x + 5) - 3(x + 5) \\ \\ = > (x + 5)(2x - 3)`

Answer 2

The equation in standard form should be 2x^2 + 7x - 15 = 0

Factored the expression is (2x - 3)(x + 5).

In order to find the factored portion, you must look for factors of the front number (2) to use in the front of the parenthesis and factors of the last number (-15) to go in the end.

When we use the ones that we have above, it distributes to the overall end result.

(2x - 3)(x + 5)
2x^2 - 3x + 10x - 15
2x^2 + 7x - 15