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What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.22?

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pH = - log [H_(3)O^(+)] \\ \\ -pH=log [H_(3)O^(+)] \\ \\ \ [H_(3)O^(+)]=10^(-pH)=10^(-4.22)= 6.03*10^(-5)M \\ \\ \ [H_(3)O^(+)]*[OH^(-)]=10^(-14) \\ \\ \ [OH^(-)] = 10^(-14)/[H_(3)O^(+)]= 10^(-14)/6.03*10^(-5)=1.66*10^(-10) M
User Arhuaco
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