Question

If you made up a solution of NaOH by adding 0.010 mole of solid NaOH to 1.0 liter of distilled water, what would be the concentration of the OH-(aq)?

Answer 1

0.01M OR 1 x10 ^-2M

Step-by-step explanation:

Odyssey ware

Answer 2

Answer is 0.01 M.

Explantion :

NaOH is a strong base which fully dissociates into its ions in water as Na⁺ and OH⁻.

NaOH(s) → Na⁺(aq) + OH⁻(aq)

The stoichiometric ratio between NaOH(s) and OH⁻(aq) is 1 : 1.

Hence,
moles of OH⁻(aq) = moles of NaOH(s)
= 0.010 mol

Concentration (M) = moles of solute (mol) / volume of the solution (L)

Hence,
concentration of OH⁻(aq) = 0.010 mol / 1.0 L
= 0.01 M