Question

The length of a rectangle is 11 ft longer than twice the width. if the perimeter is 118 ​ft, find the length and width of the rectangle.

Answer 1

A) L = 2W + 11

B) 2 L + 2 W = 118
A) L -2W = + 11
Adding A) and B) we get:
3L = 129
Length = 43
B) 2 * 43 + 2W = 118
B) 2W = 118 -86
B) 2W = 32
B) Width = 16