534,044 views
39 votes
39 votes
The product of −16 and the difference of u and v.

User Andrew Hulterstrom
by
2.9k points

1 Answer

15 votes
15 votes

I don't know if u want this but ya :)

Solution:

Let f(x) = (x+3)^(1/3).

First, we have

lim_(x → -3) f(x) = (-3+3)^(1/3) = 0 = f(-3)

So f(x) is continuous at a = -3.

Next we have

lim_(h → 0) [f(-3+h) - f(-3)] / h

= lim_(h → 0) h^(1/3) / h

= lim_(h → 0) 1 / h^(2/3)

= infty

Since the limit does not exist, f(x) is not differentiable at a = -3.

Answer: D

User RPaul
by
3.1k points
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