Question

When the pressure that a gas exerts on a sealed container changes from 893 mm hg to 778 mm hg, the temperature changes from 49.3 degrees C to degrees C?

Answer 1

7.8 degrees Celsius

Answer 2

Answer: The final temperature of the gas is 7.58 °C.

Step-by-step explanation: We are given initial and final pressure of the system and we need to find the final temperature of the system.

To calculate it, we use the equation given by Gay-Lussac.

His law states that pressure is directly related to the temperature of the gas.

`P\propto T`

Or,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1` = initial pressure = 893 mmHg = 1.175atm (Conversion factor: 1atm = 760mmHg)

`T_1` = initial temperature = 49.3°C = [49.3 + 273.15]K = 322.45K

`P_2` = Final pressure = 778mmHg = 1.023atm

`T_` = Final temperature = ?°C

Putting values in above equation, we get:

`(1.175atm)/(322.45K)=(1.023atm)/(T_2)\\\\T_2=280.73K`

Converting Final temperature from kelvin to degree Celsius.

`T_2=280.73K=[280.73-273.15]^oC=7.58^oC`

Hence, the final temperature of the gas is 7.58 °C.