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How do you simplify b^2 -3b-10/ (b-2)^2 * b-2/b-5

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Written out correctly, that would look like this:
(b^2-3b-10)/((b-2)^2) * (b-2)/(b-5). The first thing we are going to do is try to factor that quadratic. Anytime you see a second degree polynomial or higher, chances are you are going to be doing something with it that involves factoring. If we factor that we have this:
((b-5)(b+2))/((b-2)(b-2)) * (b-2)/(b-5). Now we can see more easily what we can cross cancel to simplify. One (b-2) on the bottom left cancels with the (b-2) top right. One (b-5) top left cancels with the (b-5) lower left. What that leaves us with in the end is
(b+2)/(b-2). That is as simple as you can get.
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