Question

For the graph x = 12 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your answer with two or more sentences

Answer 1

Answer:check the picture below.

that's the line of x = 12, just a straight vertical line, notice the green line, that's parallel to it, and the red line, that's perpendicular to it.

let's pick two points for each to get their slopes, hmm say for the green one (5,2) and (5,4)

and for the red one hmmm (3,2) and (7,2)

Explanation:

Answer 2

check the picture below.

that's the line of x = 12, just a straight vertical line, notice the green line, that's parallel to it, and the red line, that's perpendicular to it.

let's pick two points for each to get their slopes, hmm say for the green one (5,2) and (5,4)


`\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{4}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-2}{5-5}\implies \stackrel{und efined}{\cfrac{2}{0}}`

and for the red one hmmm (3,2) and (7,2)


`\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{2}) \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-2}{7-3}\implies \cfrac{0}{4}\implies 0`