20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?

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asked Jul 4, 2019 222k views

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Virolino · Answer 1 · 2019-07-08T11:14:33+0000

Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
Work done is force x distance
so Work done = 0.085 x 20g x 28
= 466.956 J

20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?

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