Question

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0.8 seconds when caught. If the softball has a mass of 0.2 kilograms, what’s the force of the impact? Use F = ma, where . The force of the impact is newtons.

Answer 1

The answer is 8 newtons force

Step-by-step explanation:

This is the correct answer on Plato, and this is true according to the following equations:

a= 0-32/ 0.8

= -40

0.2 * -40= -8

force can not be negative so it is 8 newtons force

Answer 2

Answer
8 Newtons

Explanation
The first step is to calculate the acceleration (a) of the ball.

a = (v-u)/t
where a⇒acceleration
v ⇒final velocity = 0 m/s
u ⇒initial velocity =32 m/s

∴a = (0 - 32)/0.8
= -40m/s²
The acceleration is negative indication the softball was decelerating.

Now force of impact;

F = ma
where m⇒ mass of the softball in kilogram

F = 0.2×-40
= -8

But force can not be negative,
So, impact force =8 Newtons