Question

Which ordered pair makes both inequalities true?

y > –2x + 3

y < x – 2


(0,0)
(0,–1)
(1,1)
(3,0)

Answer 1

The correct ordered pair is (3, 0).

You can find this by trying them in the equations and looking for true statements.

y > -2x + 3
0 > -2(3) + 3
0 > -6 + 3
0 > -3 (TRUE)

y < x - 2
0 < 3 - 2
0 < 1 (TRUE)

Since both of those are true, the pair works.

Answer 2

(3,0)

Explanation:

Given inequalities,

y > –2x + 3

y < x – 2,

For (0,0),

0 > -2(0) + 3 ( False )

For (0,-1),

-1 > -2(0) + 3 ( False )

For (1, 1),

1 > -2(1) + 3 ( False )

For (3,0),

0 > -2(3) + 3 ( True )

0 < 3 - 2 ( True )

Hence, the order pair that makes both inequality true is,

( 3, 0)