Question

What is the sixth root of (2/3)^2 as a power

Answer 1

What that looks like under a radical is this:
`\sqrt[6]{( (2)/(3)) ^(2) }`. The 6 is called the index and will replace the denominator in our power, and the 2 is the power on the base 2/3 which will replace the numerator in our final exponent. So what we have, rewritten, is this:
`( (2)/(3) ) ^{ (2)/(6) }`. Of course that exponent can be reduced so what the actual exponent is is 1/3. Our final simplified expression is
`(2)/(3) ^{ (1)/(3) }`