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What is the value of x in the equaton

{25}x^(2) = 16

1 Answer

2 votes

25x^2=16\ \ \ |:25\\\\x^2=(16)/(25)\to x=\pm\sqrt{(16)/(25)}\\\\x=-(√(16))/(√(25))\ \vee\ x=(√(16))/(√(25))\\\\\boxed{x=-(4)/(5)\ \vee\ x=(4)/(5)}
User Xarvalus
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