84.9k views
0 votes
A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h, of the basketball after t seconds. Describe the height, rounded to the nearest tenth of a foot, of the basketball after 1.5 seconds, assuming no other player touches the ball. a0 feet above the ground

1 Answer

4 votes
1.5 is a measurement of time, the t in our equation. The "h=" is "height equals". We can find out what h equals at a t value of 1.5 by subbing in 1.5 for t in the equation. That h value reflects the height of the ball thrown by a player 6 feet tall at an initial velocity of 25 ft/sec after 1.5 seconds.
h(1.5)=-16(1.5)^2+25(1.5)+6. Doing that math gives us a height of 7.5 feet.
User Npup
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories