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PLEASE ANSWER I NEED DONE

In the figure, OA = r and OC = R. The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is .

R^2/r^2
R/r
(R^2 - r^2)/r^2
1

User Shivanshu
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1 Answer

6 votes

Answer:

The other answer is wrong. It is r^2/R^2.

Explanation:

User Ldoogy
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6.4k points